Alex Rivera | Logout

How to use namespace returned by parse_known_args?

Asked 2011-07-26T19:49:35.373
9

I am currently writing a Python script and trying to dynamically generate some arguments. However, an error is being thrown for the following script, stating 'Namespace' object is not iterable. Any ideas on how to fix?

import argparse
from os import path
import re

replacements = {}
pattern = '<<([^>]*)>>'

def user_replace(match):
   ## Pull from replacements dict or prompt
    placeholder = match.group(1)
    return (replacements[placeholder][0] 
         if placeholder in replacements else 
          raw_input('%s? ' % placeholder))

def main():
    parser = argparse.ArgumentParser()
    parser.add_argument('infile', type=argparse.FileType('r'))
    parser.add_argument('outfile', type=argparse.FileType('w'))

    required, extra = parser.parse_known_args()
    infile, outfile = required.infile, required.outfile
    args = re.findall(pattern, infile.read())
    args = list(set(args))
    infile.seek(0)

    parser = argparse.ArgumentParser()
    for arg in args:
        parser.add_argument('--' + arg.lower())

    replacements = vars(parser.parse_args(extra))

    matcher = re.compile(pattern)

    for line in args.infile:
        new_line = matcher.sub(user_replace, line)
        args.outfile.write(new_line)

    args.infile.close()
    args.outfile.close()

if __name__ == '__main__':
    main()

The error is with the returned value of parser.parse_known_args(). Any ideas on how I could bypass this though? Someone suggested creating an object and using the dict interface, but I don't know what this entails exactly. I'm really new to Python, so I don't understand why (infile, outfile), extra = parser.parse_known_args() wouldn't work.

Edit: Updated with two fixes. First fixed the error above by using the accepted answer below. Second, also fixed an error where I was getting flagged for trying to add the same argument twice. Fixed by making args a set then back to a list. Now my

Edit
Report

1 Answer

0

Actually, that line of code should read as follows:

namespace= parser.parse_known_args()

Otherwise, one still gets the error about namespaces not being iterable.

answered 2011-12-11T21:38:52.950

Your Answer