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Alex Rivera
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I am having problems calling a URL from PHP code. I need to call a service using a query string from my PHP code. If I type the URL into a browser, it works ok, but if I use file-get-contents() to make the call, I get: Warning: file-get-contents(http://.... ) failed to open stream: HTTP request failed! HTTP/1.1 202 Accepted in ... The code I am using is: $query=file_get_contents('http://###.##.##.##/mp/get?mpsrc=http://mybucket.s3.amazonaws.com/11111.mpg&mpaction=convert format=flv'); echo($query); Like I said - call from the browser and it works fine. Any suggestions? I have also tried with another URL such as: $query=file_get_contents('http://www.youtube.com/watch?v=XiFrfeJ8dKM'); This works fine... could it be that the URL I need to call has a second http:// in it?
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