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Is volatile bool for thread control considered wrong?

Asked 2011-08-09T11:17:52.347
36

As a result of my answer to this question, I started reading about the keyword volatile and what the consensus is regarding it. I see there is a lot of information about it, some old which seems wrong now and a lot new which says it has almost no place in multi-threaded programming. Hence, I'd like to clarify a specific usage (couldn't find an exact answer here on SO).

I also want to point out I do understand the requirements for writing multi-threaded code in general and why volatile is not solving things. Still, I see code using volatile for thread control in code bases I work in. Further, this is the only case I use the volatile keyword as all other shared resources are properly synchronized.

Say we have a class like:

class SomeWorker
{
public:
    SomeWorker() : isRunning_(false) {}
    void start() { isRunning_ = true; /* spawns thread and calls run */ }
    void stop() { isRunning_ = false; }

private:
    void run()
    {
        while (isRunning_)
        {
            // do something
        }
    }
    volatile bool isRunning_;
};

For simplicity some things are left out, but the essential thing is that an object is created which does something in a newly spawned thread checking a (volatile) boolean to know if it should stop. This boolean value is set from another thread whenever it wants the worker to stop.

My understanding has been that the reason to use volatile in this specific case is simply to avoid any optimization which would cache it in a register for the loop. Hence, resulting in an infinite loop. There is no need to properly synchronize things, because the worker thread will eventually get the new value?

I'd like to understand if this is considered completely wrong and if the right approach is to use a synchronized variable?

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1 Answer

11

volatile can be used for such purposes. However this is an extension to standard C++ by Microsoft:

Microsoft Specific

Objects declared as volatile are (...)

  • A write to a volatile object (volatile write) has Release semantics; (...)
  • A read of a volatile object (volatile read) has Acquire semantics; (...)

This allows volatile objects to be used for memory locks and releases in multithreaded applications.(emph. added)

That is, as far as I understand, when you use the Visual C++ compiler, a volatile bool is for most practical purposes an atomic<bool>.

It should be noted that newer VS versions add a /volatile switch that controls this behavior, so this only holds if /volatile:ms is active.

answered 2011-08-09T11:32:12.207

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