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Alex Rivera
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I'm having a small error in my code that I can not for the life of me figure out. I have an array of strings that are representations of binary data (after converting them from hex) for example: one index is 1011 and another is 11100. I go through the array and pad each index with 0's so that each index is eight bytes. When I try to convert these representations into actual bytes I get an error when I try to parse '11111111' The error I get is: java.lang.NumberFormatException: Value out of range. Value:"11111111" Radix:2 Here is a snippet: String source = a.get("image block"); int val; byte imageData[] = new byte[source.length()/2]; try { f.createNewFile(); FileOutputStream output = new FileOutputStream(f); for (int i=0; i<source.length(); i+=2) { val = Integer.parseInt(source.substring(i, i+2), 16); String temp = Integer.toBinaryString(val); while (temp.length() != 8) { temp = "0" + temp; } imageData[i/2] = Byte.parseByte(temp, 2); }
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