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I need to check if a file is opened "locally" (same machine or network). I'm using:
<?php
if ((substr($_SERVER['REMOTE_ADDR'],0,8) == "192.168.") || ($_SERVER['REMOTE_ADDR'] == "127.0.0.1")) {
// client is local
} else {
// client is not local
}
But I'm not sure this is the best way.
What is a more foolproof way of doing this?