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Alex Rivera
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Say I have this function: int func2() { printf("func2\n"); return 0; } Now I declare a pointer: int (*fp)(double); This should point to a function that takes a double argument and returns an int . func2 does NOT have any argument, but still when I write: fp = func2; fp(2); (with 2 being just an arbitrary number), func2` is invoked correctly. Why is that? Is there no meaning to the number of parameters I declare for a function pointer?
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