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Using a Python subprocess call to invoke a Python script

Asked 2011-08-22T19:12:06.250
62

I have a Python script that needs to invoke another Python script in the same directory. I did this:

from subprocess import call
call('somescript.py')

I get the following error:

call('somescript.py')
File "/usr/lib/python2.6/subprocess.py", line 480, in call
return Popen(*popenargs, **kwargs).wait()
File "/usr/lib/python2.6/subprocess.py", line 633, in __init__
errread, errwrite)
File "/usr/lib/python2.6/subprocess.py", line 1139, in _execute_child

raise child_exception
OSError: [Errno 2] No such file or directory

I have the script somescript.py in the same folder though. Am I missing something here?

python subprocess
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2 Answers

2

If you're on Linux/Unix you could avoid call() altogether and not execute an entirely new instance of the Python executable and its environment.

import os

cpid = os.fork()
if not cpid:
    import somescript
    os._exit(0)

os.waitpid(cpid, 0)

For what it's worth.

answered 2011-08-22T20:19:23.810
0

First, check if somescript.py is executable and starts with something along the lines of #!/usr/bin/python. If this is done, then you can use subprocess.call('./somescript.py').

Or as another answer points out, you could do subprocess.call(['python', 'somescript.py']).

answered 2011-08-22T19:26:56.910

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