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Suppose I have the number 'numb'=1025 [00000000 00000000 00000100 00000001] represented: On Little-Endian Machine: 00000001 00000100 00000000 00000000 On Big-Endian Machine: 00000000 00000000 00000100 00000001 Now, if I apply Left Shift on 10 bits (i.e.: numb <<= 10), I should have: [A] On Little-Endian Machine: As I noticed in GDB, Little Endian does the Left Shift in 3 steps: [I have shown '3' Steps to better understand the processing only] Treat the no. in Big-Endian Convention: 00000000 00000000 00000100 00000001 Apply Left-Shift: 00000000 00010000 00000100 00000000 Represent the Result again in Little-Endian: 00000000 00000100 00010000 00000000 [B]. On Big-Endian Machine: 00000000 00010000 00000100 00000000 My Question is: If I directly apply a Left Shift on the Little Endian Convention, it should give: numb : 00000001 00000100 00000000 00000000 numb << 10 : 00010000 00000000 00000000 00000000 But actually, it gives: 00000000 00000100 00010000 00000000 To achieve the second result only, I have shown three hypothetical steps above. Please explain me why the above two results are different: The actual outcome of numb << 10 is different than the expected outcome.

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