Edit Question - KnowledgeHub

Title Body

I have a C function that takes a function pointer as argument, it's a destructor that I'll call at the end of my program. Here is the prototype of my function : int store_dest(void (*routine)(void *)); I want to store this function pointer into a structure with some other infos. In order to have a nice struct, I want to have a typedef to this function pointer. Here is my typedef : typedef void (*my_destructor)(void *); And here is my structure : typedef struct my_struct{ my_destructor dest; other_info ... } my_struct; During the initialization step, I want to set the "dest" field to a function of mine, here is the prototype of this function : void* my_dummy_dest(void* foo); The problem (in fact it's just a warning but I'd like to suppress it) occurs when I try to set the "dest" field of my structure to "my_dummy_dest" : my_struct.dest = &my_dummy_dest; I get a "warning: assignment from incompatible pointer type" Same when I just compare them : if (my_struct.dest == &my_dummy_dest) I get a "warning: comparison of distinct pointer types lacks a cast" But I get no warning when I set the "dest" field with another routine. I don't get why I have those warnings.

Tags (comma-separated) Cancel