Alex Rivera | Logout

Why won't re.groups() give me anything for my one correctly-matched group?

Asked 2011-09-05T19:24:43.923
34

When I run this code:

print re.search(r'1', '1').groups() 

I get a result of (). However, .group(0) gives me the match.

Shouldn't groups() give me something containing the match?

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2 Answers

26

To the best of my knowledge, .groups() returns a tuple of remembered groups. I.e. those groups in the regular expression that are enclosed in parentheses. So if you were to write:

print re.search(r'(1)', '1').groups()

you would get

('1',)

as your response. In general, .groups() will return a tuple of all the groups of objects in the regular expression that are enclosed within parentheses.

answered 2011-09-05T19:39:44.570
23

groups is empty since you do not have any capturing groups - http://docs.python.org/library/re.html#re.MatchObject.groups. group(0) will always returns the whole text that was matched regardless of if it was captured in a group or not

Edited.

answered 2011-09-05T19:28:48.837

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