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Alex Rivera
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Today I found out that code like that works. That sounds really strange to me, because as far as I always knew you can't modify any of members from const member function. You actually can't do it directly, but you can call non-const member function. if you mark member function as const that means that this pointer passed to the function is pointing to const object, then how non-const member function is called in the example bellow? #include <iostream> class X { public: void foo() const { ptr->bar(); } void bar() {} private: X * ptr; }; int main() { }
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