In the following, would there be a temporary object created before const reference is used to a non-const object?

const int y = 2000;
const int &s = y // ok, const reference to const object.

int x = 1000;
const int &r = x; // any temporary copy here?

If no then, how does this work?

   const int z = 3000;
   int &t = z // ok, why can't you do this?
c++ reference const-correctness
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