Alex Rivera | Logout

Numbered listbox

Asked 2009-04-13T22:07:35.937
25

I have a sorted listbox and need to display each item's row number. In this demo I have a Person class with a Name string property. The listbox displays a a list of Persons sorted by Name. How can I add to the datatemplate of the listbox the row number???

XAML:

<Window x:Class="NumberedListBox.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Height="300" Width="300">
    <ListBox 
        ItemsSource="{Binding Path=PersonsListCollectionView}" 
        HorizontalContentAlignment="Stretch">
        <ListBox.ItemTemplate>
            <DataTemplate>
                <TextBlock Text="{Binding Path=Name}" />
            </DataTemplate>
        </ListBox.ItemTemplate>
    </ListBox>
</Window>

Code behind:

using System;
using System.Collections.ObjectModel;
using System.Windows.Data;
using System.Windows;
using System.ComponentModel;

namespace NumberedListBox
{
    public partial class Window1 : Window
    {
        public Window1()
        {
            InitializeComponent();

            Persons = new ObservableCollection<Person>();
            Persons.Add(new Person() { Name = "Sally"});
            Persons.Add(new Person() { Name = "Bob" });
            Persons.Add(new Person() { Name = "Joe" });
            Persons.Add(new Person() { Name = "Mary" });

            PersonsListCollectionView = new ListCollectionView(Persons);
            PersonsListCollectionView.SortDescriptions.Add(new SortDescription("Name", ListSortDirection.Ascending));

            DataContext = this;
        }

        public ObservableCollection<Person> Persons { get; private set; }
        public ListCollectionView PersonsListCollectionView { get; private set; }
    }

    public class Person
    {
        public string Name { get; set; }
  
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1 Answer

4

The idea in David Brown's link was to use a value converter which worked. Below is a full working sample. The list box has row numbers and can be sorted on both name and age.

XAML:

<Window x:Class="NumberedListBox.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    xmlns:local="clr-namespace:NumberedListBox"
    Height="300" Width="300">

    <Window.Resources>

        <local:RowNumberConverter x:Key="RowNumberConverter" />

        <CollectionViewSource x:Key="sortedPersonList" Source="{Binding Path=Persons}" />

    </Window.Resources>

    <Grid>
        <Grid.RowDefinitions>
            <RowDefinition />
            <RowDefinition Height="Auto"/>
        </Grid.RowDefinitions>
        <Grid.ColumnDefinitions>
            <ColumnDefinition />
            <ColumnDefinition />
        </Grid.ColumnDefinitions>
        <ListBox 
            Grid.Row="0" Grid.Column="0" Grid.ColumnSpan="2"
            ItemsSource="{Binding Source={StaticResource sortedPersonList}}" 
            HorizontalContentAlignment="Stretch">
            <ListBox.ItemTemplate>
                <DataTemplate>
                    <StackPanel Orientation="Horizontal">
                        <TextBlock 
                            Text="{Binding Converter={StaticResource RowNumberConverter}, ConverterParameter={StaticResource sortedPersonList}}" 
                            Margin="5" />
                        <TextBlock Text="{Binding Path=Name}" Margin="5" />
                        <TextBlock Text="{Binding Path=Age}" Margin="5" />
                    </StackPanel>
                </DataTemplate>
            </ListBox.ItemTemplate>
        </ListBox>
        <Button Grid.Row="1" Grid.Column
answered 2009-04-14T16:31:43.850

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