Is operator && strict in Haskell?

For example, I have an operation fnB :: a -> Bool that makes no sense until fnA :: Bool returns False. In C I may compose these two operations in one if block:

if( fnA && fnB(a) ){ doSomething; }

and C will guarantee that fnB will not execute until fnA returns false.

But Haskell is lazy, and, generally, there is no guarantee what operation will execute first, until we don't use seq, $!, or something else to make our code strict. Generally, this is what we need to be happy. But using && operator, I would expect that fnB will not be evaluated until fnA returns its result. Does Haskell provide such a guarantee with &&? And will Haskell evaluate fnB even when fnA returns False?