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Makefile run processes in background

Asked 2011-10-05T22:04:39.683
16

I have this in my Makefile:

run:
     for x in *.bin ; do ./$$x ; done

such that it launches all executables one by one. I want to do this:

run:
     for x in *.bin ; do ./$$x &; done

so that it starts each executable and puts it in the background. I get a syntax error for the above statement when I put the ampersand.

I dont want to invoke the make as make & since this will run processes in the background but still one by one, whereas I want individual executables to run in the background, so that at any instant I have more than one executable running.

Thank you in advance.

makefile parallel-processing
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1 Answer

20

Try to execute via a subshell:

run:
     for x in *.bin ; do (./$$x &); done

Maybe make -j is a better option. Try a Makefile that looks something like this:

BINS = $(shell echo *.bin)

.PHONY: $(BINS)
run: $(BINS)

*.bin:
    ./$@

And then execute with make -j <jobs> where <jobs> is number of simultaneous jobs to run.

answered 2011-10-05T22:11:06.893

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