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Alex Rivera
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I've stumbled upon an issue with CInt and converting a double to an integer. The issue is the following: CInt(10.5) 'Result is 10 CInt(10.51) 'Result it 11, but I expected 10... I got used to C# style conversion where (int) 10.51 is 10. As pointed out in the question about Integer.Parse vs CInt , the result is just rounded in some fashion. However, all I need is to get only integer part and throw away the fractional one. How can I achieve such type of conversion in VB.NET? After some research I see that I can use the Fix() function to do the trick, but is it the best choice?
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