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Alex Rivera
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if (phpversion() >= '4.3.0'){ $string = mysqli_real_escape_string($string); }else{ $string = mysqli_escape_string($string); } All the documentation for mysqli_real_escape_string seems to indicate this is a valid bit of code, but I don't understand why I get this error: mysqli_real_escape_string() expects exactly 2 parameters, 1 given
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