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I have to write a script that finds all executable files in a directory. So I tried several ways to implement it and they actually work. But I wonder if there is a nicer way to do so. So this was my first approach: ls -Fla | grep \*$ This works fine, because the -F flag does the work for me and adds to each executable file an asterisk, but let's say I don't like the asterisk sign. So this was the second approach: ls -la | grep -E ^-.{2}x This too works fine, I want a dash as first character, then I'm not interested in the next two characters and the fourth character must be a x. But there's a bit of ambiguity in the requirements, because I don't know whether I have to check for user, group or other executable permission. So this would work: ls -la | grep -E ^-.{2}x\|^-.{5}x\|^-.{8}x So I'm testing the fourth, seventh and tenth character to be a x. Now my real question, is there a better solution using ls and grep with regex to say: I want to grep only those files, having at least one x in the ten first characters of a line produced by ls -la

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