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Question as above, more details below: I have a class Money to deal with... well, you guessed what. I am very strict about not allowing Money and double to interact(*), so the following code is not possible: Money m1( 4.50 ); double d = 1.5; Money m2 = m1 * d; // <-- compiler error Now I'm thinking about allowing multiplication of Money with int , as in "you have 6 pieces of cake for $4.50 each (so go and find cheaper cake somewhere)." class Money { Money(); Money( const Money & other ); explicit Money( double d ); ... Money & operator*=( int i ); ... } inline const Money operator*( const Money & m, int i ) { return Money( m ) *= i; } inline const Money operator*( int i, const Money & m ) { return Money( m ) *= i; } That works fine, but ... unfortunately, C++ does implicit casts from double to int , so suddenly my first code snippet will compile. I don't want that. Is there any way to prevent implicit casts in this situation? Thanks! -- Robin (*) Reason: I have lot's of legacy code that handles all Money -related stuff with double , and I don't want those types confused until everything run with Money . Edit: Added constructors for Money. Edit: Thanks, everyone, for your answers. Almost all of them were great and helpful. R. Martinho Fernandes' comment "you can do inline const Money operator*( const Money & m, double d ) = delete; " was actually the answer (as soon as I switch to a C++11-supporting compiler). Kerrek SB gave a good none-C++11 alternative, but what I ended up with using is actually Nicola Musatti's "overload long " approach. That's why I'm flagging his answer as "the answer" (also because all the use

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