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What is the Java ?: operator called and what does it do?

Asked 2009-04-28T15:28:50.420
205

I have been working with Java a couple of years, but up until recently I haven't run across this construct:

int count = isHere ? getHereCount(index) : getAwayCount(index);

This is probably a very simple question, but can someone explain it? How do I read it? I am pretty sure I know how it works.

  • if isHere is true, getHereCount() is called,
  • if isHere is false getAwayCount() is called.

Correct? What is this construct called?

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3 Answers

34

Others have answered this to reasonable extent, but often with the name "ternary operator".

Being the pedant that I am, I'd like to make it clear that the name of the operator is the conditional operator or "conditional operator ?:". It's a ternary operator (in that it has three operands) and it happens to be the only ternary operator in Java at the moment.

However, the spec is pretty clear that its name is the conditional operator or "conditional operator ?:" to be absolutely unambiguous. I think it's clearer to call it by that name, as it indicates the behaviour of the operator to some extent (evaluating a condition) rather than just how many operands it has.

answered 2009-04-28T15:36:40.260
5

Not exactly correct, to be precise:

  1. if isHere is true, the result of getHereCount() is returned
  2. otheriwse the result of getAwayCount() is returned

That "returned" is very important. It means the methods must return a value and that value must be assigned somewhere.

Also, it's not exactly syntactically equivalent to the if-else version. For example:

String str1,str2,str3,str4;
boolean check;
//...
return str1 + (check ? str2 : str3) + str4;

If coded with if-else will always result in more bytecode.

answered 2009-04-28T16:03:26.687
2

Correct. It's called the ternary operator. Some also call it the conditional operator.

answered 2009-04-28T15:30:31.087

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