Implicit type conversion in C

I stumbled upon the following example on wikipedia (http://en.wikipedia.org/wiki/Type_conversion#Implicit_type_conversion).

#include <stdio.h>

int main()
{
    int i_value   = 16777217;
    float f_value = 16777217.0;
    printf("The integer is: %i\n", i_value); // 16777217
    printf("The float is:   %f\n", f_value); // 16777216.000000
    printf("Their equality: %i\n", i_value == f_value); // result is 0
}

Their explanation: "This odd behavior is caused by an implicit cast of i_value to float when it is compared with f_value; a cast which loses precision, making the values being compared different."

Isn't this wrong? If i_value were cast to float, then both would have the same loss in precision and they would be equal. So i_value must be cast to double.