Recently I discovered that C#'s operator % is applicable to double. Tried some things out, and after all came up with this test:

class Program
{
    static void test(double a, double b)
    {
        if (a % b != a - b * Math.Truncate(a / b))
        {
            Console.WriteLine(a + ", " + b);
        }
    }
    static void Main(string[] args)
    {
        test(2.5, 7);
        test(-6.7, -3);
        test(8.7, 4);
        //...
    }
}

Everything in this test works. Is a % b always equivalent to a - b*Math.Round(a/b)? If not, please explain to me how this operator really works.

EDIT: Answering to James L, I understand that this is a modulo operator and everything. I'm curious only about how it works with double, integers I understand.

c# modulo
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