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Alex Rivera
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Do I really have to encapsulate the std::move call in a lambda? std::list<std::wstring> srcData = GetData(); // implementation not important std::vector<std::wstring> dstData; dstData.reserve(srcData.size()); std::transform(std::begin(srcData), std::end(srcData), std::back_inserter(dstData), [](std::wstring& guid) -> std::wstring { return std::move(guid); }); srcData.clear(); I am still new to lambdas and rvalue references, so initially I tried: std::transform(std::begin(srcData), std::end(srcData), std::back_inserter(dstData), &std::move<std::wstring>); which doesn't work. Do I have to put the move inside a lambda, or am I missing something obvious?
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