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I have a list of lists:
lst = [[567, 345, 234], [253, 465, 756, 2345], [333, 777, 111, 555]]
I want map lst into another list containing only the second smallest number from each sublist. So the result should be [345, 465, 333].
If I were just interested in the smallest number, I could write this as map(lambda x: min(x), lst). To get the second smallest numbers, I thought of sorting and then indexing the results, like map(lambda x: sort(x)[1], lst); however, sort returns None rather than chaining.
If it were possible to use multiple statements in a lambda, I could write map(lambda x: sort(x); x[1], lst), but this is not allowed.
Can I use map to solve the problem without defining a named function? How?