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See the definition of TCP header in /netinet/tcp.h: struct tcphdr { u_int16_t th_sport; /* source port */ u_int16_t th_dport; /* destination port */ tcp_seq th_seq; /* sequence number */ tcp_seq th_ack; /* acknowledgement number */ # if __BYTE_ORDER == __LITTLE_ENDIAN u_int8_t th_x2:4; /* (unused) */ u_int8_t th_off:4; /* data offset */ # endif # if __BYTE_ORDER == __BIG_ENDIAN u_int8_t th_off:4; /* data offset */ u_int8_t th_x2:4; /* (unused) */ # endif u_int8_t th_flags; # define TH_FIN 0x01 # define TH_SYN 0x02 # define TH_RST 0x04 # define TH_PUSH 0x08 # define TH_ACK 0x10 # define TH_URG 0x20 u_int16_t th_win; /* window */ u_int16_t th_sum; /* checksum */ u_int16_t th_urp; /* urgent pointer */ }; Why does the 8-bit field have a different order in endianness? I thought only 16-bit and 32-bit fields mattered with byte order, and you could convert between endians with ntohs and ntohl, respectively. What would the function be for handling 8-bit things? If there is none, it seems that a TCP using this header on a little endian machine would not work with a TCP on a big endian machine.

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