Position of the sun given time of day, latitude and longitude

This question has been asked before a little over three years ago. There was an answer given, however I've found a glitch in the solution.

Code below is in R. I've ported it to another language, however have tested the original code directly in R to ensure the issue wasn't with my porting.

sunPosition <- function(year, month, day, hour=12, min=0, sec=0,
                    lat=46.5, long=6.5) {


  twopi <- 2 * pi
  deg2rad <- pi / 180

  # Get day of the year, e.g. Feb 1 = 32, Mar 1 = 61 on leap years
  month.days <- c(0,31,28,31,30,31,30,31,31,30,31,30)
  day <- day + cumsum(month.days)[month]
  leapdays <- year %% 4 == 0 & (year %% 400 == 0 | year %% 100 != 0) & day >= 60
  day[leapdays] <- day[leapdays] + 1

  # Get Julian date - 2400000
  hour <- hour + min / 60 + sec / 3600 # hour plus fraction
  delta <- year - 1949
  leap <- trunc(delta / 4) # former leapyears
  jd <- 32916.5 + delta * 365 + leap + day + hour / 24

  # The input to the Atronomer's almanach is the difference between
  # the Julian date and JD 2451545.0 (noon, 1 January 2000)
  time <- jd - 51545.

  # Ecliptic coordinates

  # Mean longitude
  mnlong <- 280.460 + .9856474 * time
  mnlong <- mnlong %% 360
  mnlong[mnlong < 0] <- mnlong[mnlong < 0] + 360

  # Mean anomaly
  mnanom <- 357.528 + .9856003 * time
  mnanom <- mnanom %% 360
  mnanom[mnanom < 0] <- mnanom[mnanom < 0] + 360
  mnanom <- mnanom * deg2rad

  # Ecliptic longitude and obliquity of ecliptic
  eclong <- mnlong + 1.915 * sin(mnanom) + 0.020 * sin(2 * mnanom)
  eclong <- eclong %% 360
  eclong[eclong < 0] <- eclong[eclong < 0] + 360
  oblqec <- 23.429 - 0.0000004 * time
  eclong <- eclong * deg2rad
  oblqec <- oblqec * deg2rad

  # Celestial coordinates
  # Right