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I'm trying to start a simple service example: someservice.py: import win32serviceutil import win32service import win32event class SmallestPythonService(win32serviceutil.ServiceFramework): _svc_name_ = "SmallestPythonService" _svc_display_name_ = "display service" def __init__(self, args): win32serviceutil.ServiceFramework.__init__(self, args) self.hWaitStop = win32event.CreateEvent(None, 0, 0, None) def SvcStop(self): self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING) win32event.SetEvent(self.hWaitStop) def SvcDoRun(self): win32event.WaitForSingleObject(self.hWaitStop, win32event.INFINITE) if __name__=='__main__': win32serviceutil.HandleCommandLine(SmallestPythonService) When I run python someservice.py install everything is fine and the service appears in the Windows service list, but python someservice.py start fails with "Error 1053: The service did not respond to the start or control request in a timely fashion", but there is not any delay. I googled a solution, which said it happens when pythonservice.exe can't locate python27.dll . It actually couldn't so I added C:\Python27 to PATH . Now pythonservice.exe runs fine, but Error 1053 still there. I'm running Python 2.7.2 with pywin32 216 on Windows 7 Ultimate with admin privilegies.

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