Haskell How to Create a Word8?

I want to write a simple function which splits a ByteString into [ByteString] using '\n' as the delimiter. My attempt:

import Data.ByteString

listize :: ByteString -> [ByteString]
listize xs = Data.ByteString.splitWith (=='\n') xs

This throws an error because '\n' is a Char rather than a Word8, which is what Data.ByteString.splitWith is expecting.

How do I turn this simple character into a Word8 that ByteString will play with?