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Alex Rivera
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This is a follow up of this problem: Generic functor for functions with any argument list I have this functor class (full code see link above): template<typename... ARGS> class Foo { std::function<void(ARGS...)> m_f; public: Foo(std::function<void(ARGS...)> f) : m_f(f) {} void operator()(ARGS... args) const { m_f(args...); } }; In operator() I can access the args... easily with a recursive "peeling" function as described in Stroustrup's C++11 FAQ My problem is: I want to access the types of the arguments of f, i.e. ARGS... , in the constructor. Obviously I can't access values because there are none so far, but the argument type list is somehow burried in f , isn't it?
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