9
when a C# program holds a named semaphore, it does not seem to be released when the application is terminated early (for example by pressing Ctrl+C or closing the console window). At least not until all instances of the process have terminated.
With a named mutex an AbandonedMutexException is raised in this case but not with a semaphore. How do you prevent one program instance from stalling when another program instance has been terminated early?
class Program
{
// Same with count > 1
private static Semaphore mySemaphore = new Semaphore(1, 1, "SemaphoreTest");
static void Main(string[] args)
{
try
{
// Blocks forever if the first process was terminated
// before it had the chance to call Release
Console.WriteLine("Getting semaphore");
mySemaphore.WaitOne();
Console.WriteLine("Acquired...");
}
catch (AbandonedMutexException)
{
// Never called!
Console.WriteLine("Acquired due to AbandonedMutexException...");
}
catch (System.Exception ex)
{
Console.WriteLine(ex);
}
Thread.Sleep(20 * 1000);
mySemaphore.Release();
Console.WriteLine("Done");
}
}