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Alex Rivera
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Is there a way to have an argparse.ArgumentParser not raise an exception upon reading an unknown option, but rather put all the unknown options with values in a dictionary, and those without a value in a list? For example, say no arguments were defined in the parser for prog.py , and I pass two arguments: ./prog.py --foo bar --baz I would like the following: parsed = parser.parse_args() vals = parsed.unknown_with_vals novals = parsed.unknown_without_vals print(vals) #{'foo' : 'bar'} print(novals) #['baz'] Can this be done?
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