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I am facing a GCC warning that I want to fix. Basically I am passing to a method a pointer to a local variable, which in my case is perfectly OK. I understand why the compiler tells me that this is a potential problem, but in my case this is OK. How can I workaround it, on a local space? Passing -fpermissive when compiling will make me fail to find future problems. I want to fix this specific problem, or workaround it. Code is available here: #include <cstdio> class Integer{ public: Integer(int i ){ v = i; }; int value(){ return v; }; private: int v; }; int foo(Integer *i); int main() { foo( &Integer(12) ); } int foo(Integer *i) { std::printf("Integer = %d\n", i->value()); } And compilation gives me: $ g++ test-reference.cpp -O test-reference test-reference.cpp: In function ‘int main()’: test-reference.cpp:15:18: error: taking address of temporary [-fpermissive] $ g++ --version g++ (Ubuntu/Linaro 4.6.3-1ubuntu3) 4.6.3 Copyright (C) 2011 Free Software Foundation, Inc. This is free software; see the source for copying conditions. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. EDIT: Using const (as in making foo take a const pointer, and marking value() as const) gives the same error.

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