I'm parsing unsigned bits from a DatagramSocket. I have a total of 24bits (or 3 bytes) coming in - they are: 1 unsigned 8bit integer followed by a 16bit signed integer. But java never stores anything more than a signed byte into a byte/byte array? When java takes in these values, do you lose that last 8th bit? 

DatagramSocket serverSocket = new DatagramSocket(666);
        byte[] receiveData = new byte[3]; <--Now at this moment I lost my 8th bit

        System.out.println("Binary Server Listing on Port: "+port);

        while (true)
        {
            DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length);
            serverSocket.receive(receivePacket);
            byte[] bArray = receivePacket.getData();
            byte b = bArray[0];

        }

enter image description here

Did I now lose this 8th bit since I turned it into a byte? Was it wrong I initialized a byte array of 3 bytes?

java bit-manipulation
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