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Alex Rivera
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I'm parsing unsigned bits from a DatagramSocket. I have a total of 24bits (or 3 bytes) coming in - they are: 1 unsigned 8bit integer followed by a 16bit signed integer. But java never stores anything more than a signed byte into a byte/byte array? When java takes in these values, do you lose that last 8th bit? DatagramSocket serverSocket = new DatagramSocket(666); byte[] receiveData = new byte[3]; <--Now at this moment I lost my 8th bit System.out.println("Binary Server Listing on Port: "+port); while (true) { DatagramPacket receivePacket = new DatagramPacket(receiveData, receiveData.length); serverSocket.receive(receivePacket); byte[] bArray = receivePacket.getData(); byte b = bArray[0]; } Did I now lose this 8th bit since I turned it into a byte? Was it wrong I initialized a byte array of 3 bytes?
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