I am using Jasypt-1.9.0 with Spring 3.1 and Hibernate 4.0.1. I have a requirement in my application to connect to database whose password(root) is stored in the encrypted form in the property file within the application.

I looked online and found the way with following links:

  1. http://www.jasypt.org/spring31.html

  2. http://www.jasypt.org/hibernate.html

  3. http://www.jasypt.org/encrypting-configuration.html

I have done the following steps and configuration for my requirement:

  • Added jasypt-1.9.0 and jasypt-hibernate4-1.9.0 in build path.
  • Added following in my dispatcher-servlet file:
< bean id="propertyConfigurer"
   class="org.jasypt.spring31.properties.EncryptablePropertyPlaceholderConfigurer">

  < constructor-arg ref="configurationEncryptor" />
  < property name="locations">
    < list>
      < value>classpath:database.properties< /value>
    < /list>
  < /property>
< /bean>

< bean id="configurationEncryptor"
    class="org.jasypt.encryption.pbe.StandardPBEStringEncryptor">
  < property name="config" ref="environmentVariablesConfiguration" />
< /bean>

< bean id="environmentVariablesConfiguration"
    class="org.jasypt.encryption.pbe.config.EnvironmentStringPBEConfig">
  < property name="algorithm" value="PBEWithMD5AndDES" />
  < property name="passwordEnvName" value="APP_ENCRYPTION_PASSWORD" />
</bean>
  • Using CLI tool of Jasypt 1.9.0, I have generated the password below(attached snapshot of CLI)
    spring hibernate password-encryption jasypt
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