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I am using Jasypt-1.9.0 with Spring 3.1 and Hibernate 4.0.1 . I have a requirement in my application to connect to database whose password(root) is stored in the encrypted form in the property file within the application. I looked online and found the way with following links: http://www.jasypt.org/spring31.html http://www.jasypt.org/hibernate.html http://www.jasypt.org/encrypting-configuration.html I have done the following steps and configuration for my requirement: Added jasypt-1.9.0 and jasypt-hibernate4 -1.9.0 in build path. Added following in my dispatcher-servlet file: < bean id="propertyConfigurer" class="org.jasypt.spring31.properties.EncryptablePropertyPlaceholderConfigurer"> < constructor-arg ref="configurationEncryptor" /> < property name="locations"> < list> < value>classpath:database.properties< /value> < /list> < /property> < /bean> < bean id="configurationEncryptor" class="org.jasypt.encryption.pbe.StandardPBEStringEncryptor"> < property name="config" ref="environmentVariablesConfiguration" /> < /bean> < bean id="environmentVariablesConfiguration" class="org.jasypt.encryption.pbe.config.EnvironmentStringPBEConfig"> < property name="algorithm" value="PBEWithMD5AndDES" /> < property name="passwordEnvName" value="APP_ENCRYPTION_PASSWORD" /> </bean> Using CLI tool of Jasypt 1.9.0, I have generated the password below(attached snapshot of CLI)</li

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