Assignment makes pointer from integer without a cast and other questions

I just started learning C a few days ago and I'm having a bit of difficulties with pointers. I'm trying to convert a string to an array of integers. The little snipet below seems to be working but I'm getting a warning :

In function 'charToInt32' warning: assignment makes pointer from integer without a cast [enabled by default]| ||=== Build finished: 0 errors, 1 warnings (0 minutes, 0 seconds) ===|

The warning comes from the line

int32result[pos] = returnedInteger;

So I'm trying to understand what's the best solution. Should I use strncpy (but can I use strncpy for integers?) or something else or did I just completly misunderstand pointers?

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>


    int charToInt32(char * clearText, unsigned int * int32result[])
    {
        int i = 0, j = 0, pos = 0;          /* Counters */
        int dec[4] = {24, 16, 8, 0};        /* Byte positions in an array*/
        unsigned int returnedInteger = 0;           /*   so we can change the order*/ 

        for (i=0; clearText[i]; i+=4) {
            returnedInteger = 0;
            for (j=0; j <= 3 ; j++) {
                returnedInteger |= (unsigned int) (clearText[i+j] << dec[j]) ;
            }

            int32result[pos] = returnedInteger;
            pos++;
        }
        return pos;
    }



    int main()
    {
        int i = 0;
        unsigned int * int32result[1024] = {0};
        char * clearText =  "ABCDEFGHIJKLMNOPQRSTUVWXYZ";

        printf(">>Clear: %s\n", clearText);
        charToInt32(clearText, int32result); // Do the conversion to int32.
        printf(">>Int32 converted: ");
        for (i=0; int32result[i]; i++)
            printf("%u ", (unsigned int) int32result[i]);
        printf("\n");
        return 0;
    }

Also, at the end of the program I have the following line:

printf("%u ", (un