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I just started learning C a few days ago and I'm having a bit of difficulties with pointers. I'm trying to convert a string to an array of integers. The little snipet below seems to be working but I'm getting a warning : In function 'charToInt32' warning: assignment makes pointer from integer without a cast [enabled by default]| ||=== Build finished: 0 errors, 1 warnings (0 minutes, 0 seconds) ===| The warning comes from the line int32result[pos] = returnedInteger; So I'm trying to understand what's the best solution. Should I use strncpy (but can I use strncpy for integers?) or something else or did I just completly misunderstand pointers? #include <stdio.h> #include <stdlib.h> #include <string.h> int charToInt32(char * clearText, unsigned int * int32result[]) { int i = 0, j = 0, pos = 0; /* Counters */ int dec[4] = {24, 16, 8, 0}; /* Byte positions in an array*/ unsigned int returnedInteger = 0; /* so we can change the order*/ for (i=0; clearText[i]; i+=4) { returnedInteger = 0; for (j=0; j <= 3 ; j++) { returnedInteger |= (unsigned int) (clearText[i+j] << dec[j]) ; } int32result[pos] = returnedInteger; pos++; } return pos; } int main() { int i = 0; unsigned int * int32result[1024] = {0}; char * clearText = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"; printf(">>Clear: %s\n", clearText); charToInt32(clearText, int32result); // Do the conversion to int32. printf(">>Int32 converted: "); for (i=0; int32result[i]; i++) printf("%u ", (unsigned int) int32result[i]); printf("\n"); return 0; } Also, at the end of the program I have the following line: printf("%u ", (un

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