C++ template partial specialization - specializing one member function only

Bumped into another templates problem:

The problem: I want to partially specialize a container-class (foo) for the case that the objects are pointers, and i want to specialize only the delete-method. Should look like this:

The lib code

template <typename T>
class foo
{
public:
    void addSome    (T o) { printf ("adding that object..."); }
    void deleteSome (T o) { printf ("deleting that object..."); }
};

template <typename T>
class foo <T *>
{
public:
    void deleteSome (T* o) { printf ("deleting that PTR to an object..."); }
};

The user code

foo<myclass> myclasses;
foo<myclass*> myptrs;

myptrs.addSome (new myclass());

This results into the compiler telling me that myptrs doesnt have a method called addSome. Why ?

Thanx.

Solution

lib

template <typename T>
class foobase
{
public:
    void addSome    (T o) { printf ("adding that object..."); }
    void deleteSome (T o) { printf ("deleting that object..."); }
};


template <typename T>
class foo : public foobase<T>
{ };

template <typename T>
class foo<T *> : public foobase<T *>
{
public:
    void deleteSome (T* o) { printf ("deleting that ptr to an object..."); }
};

user

foo<int>    fi;
foo<int*>   fpi;

int         i = 13;

fi.addSome (12);            
fpi.addSome (&i);

fpi.deleteSome (12);        // compiler-error: doesnt work
fi.deleteSome (&i);         // compiler-error: doesnt work
fi.deleteSome (12);         // foobase::deleteSome called
fpi.deleteSome (&i);        // foo<T*>::deleteSome called