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Bumped into another templates problem: The problem: I want to partially specialize a container-class (foo) for the case that the objects are pointers, and i want to specialize only the delete-method. Should look like this: The lib code template <typename T> class foo { public: void addSome (T o) { printf ("adding that object..."); } void deleteSome (T o) { printf ("deleting that object..."); } }; template <typename T> class foo <T *> { public: void deleteSome (T* o) { printf ("deleting that PTR to an object..."); } }; The user code foo<myclass> myclasses; foo<myclass*> myptrs; myptrs.addSome (new myclass()); This results into the compiler telling me that myptrs doesnt have a method called addSome. Why ? Thanx. Solution based on tony's answer here the fully compilable stuff lib template <typename T> class foobase { public: void addSome (T o) { printf ("adding that object..."); } void deleteSome (T o) { printf ("deleting that object..."); } }; template <typename T> class foo : public foobase<T> { }; template <typename T> class foo<T *> : public foobase<T *> { public: void deleteSome (T* o) { printf ("deleting that ptr to an object..."); } }; user foo<int> fi; foo<int*> fpi; int i = 13; fi.addSome (12); fpi.addSome (&i); fpi.deleteSome (12); // compiler-error: doesnt work fi.deleteSome (&i); // compiler-error: doesnt work fi.deleteSome (12); // foobase::deleteSome called fpi.deleteSome (&i); // foo<T*>::deleteSome called

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