Following is the wsdl file of my service:

    <wsdl:types>
      <xsd:schema targetNamespace="http://tempuri.org/Imports">
      <xsd:import schemaLocation="http://localhost:3789/VideoUpload.svc?xsd=xsd0" namespace="http://tempuri.org/" /> 
      <xsd:import schemaLocation="http://localhost:3789/VideoUpload.svc?xsd=xsd1" namespace="http://schemas.microsoft.com/2003/10/Serialization/" /> 
      <xsd:import schemaLocation="http://localhost:3789/VideoUpload.svc?xsd=xsd2" namespace="http://schemas.datacontract.org/2004/07/UploadVideoProtocol" /> 
      </xsd:schema>
    </wsdl:types>
-----
<wsdl:definitions>
<wsdl:service name="VideoUpload">
<wsdl:port name="BasicHttpBinding_IVideoUpload" binding="tns:BasicHttpBinding_IVideoUpload">
  <soap:address location="http://localhost:3789/VideoUpload.svc" /> 
  </wsdl:port>
  </wsdl:service>
</wsdl:definitions>

In the above, I could change the namespace by specifying the custom namespace inside the code in service contract and behavior.

But I need to change the endpoint address specified in the schema location,

schemaLocation="http://localhost:3789/VideoUpload.svc?xsd=xsd0"

To my own defined endpoint address as:

schemaLocation="http://myservice.com:8080/VideoUpload.svc?xsd=xsd0"

What is the procedure to achieve this? what has to be mentioned in the code to change the default endpoint generated? Can anyone please help me on this?

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