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Following is the wsdl file of my service: <wsdl:types> <xsd:schema targetNamespace="http://tempuri.org/Imports"> <xsd:import schemaLocation="http://localhost:3789/VideoUpload.svc?xsd=xsd0" namespace="http://tempuri.org/" /> <xsd:import schemaLocation="http://localhost:3789/VideoUpload.svc?xsd=xsd1" namespace="http://schemas.microsoft.com/2003/10/Serialization/" /> <xsd:import schemaLocation="http://localhost:3789/VideoUpload.svc?xsd=xsd2" namespace="http://schemas.datacontract.org/2004/07/UploadVideoProtocol" /> </xsd:schema> </wsdl:types> ----- <wsdl:definitions> <wsdl:service name="VideoUpload"> <wsdl:port name="BasicHttpBinding_IVideoUpload" binding="tns:BasicHttpBinding_IVideoUpload"> <soap:address location="http://localhost:3789/VideoUpload.svc" /> </wsdl:port> </wsdl:service> </wsdl:definitions> In the above, I could change the namespace by specifying the custom namespace inside the code in service contract and behavior. But I need to change the endpoint address specified in the schema location, schemaLocation="http://localhost:3789/VideoUpload.svc?xsd=xsd0" To my own defined endpoint address as: schemaLocation="http://myservice.com:8080/VideoUpload.svc?xsd=xsd0" What is the procedure to achieve this? what has to be mentioned in the code to change the default endpoint generated? Can anyone please help me on this?

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