Before you say its a duplicate question, please let me explain (as I've read all similar threads).

My application has both of these settings:

  procStartInfo.CreateNoWindow = true;
  procStartInfo.WindowStyle = ProcessWindowStyle.Hidden;

and is also has WindowsApplication as the output type.

The black window STILL comes up when I call a command line command. Is there anything else I can do to hide the window? It doesn't happen for all commands, XCOPY is a situation where it the black window does flash up. This only happens though when the destination I'm XCOPYing too already contains the file and it's prompting me if I want to replace it. Even if I pass in /Y it will still flash briefly.

I'm open to using vbscript if that will help, but any other ideas?

The client will call my executable and then pass in a command line command ie:

C:\MyProgram.exe start XCOPY c:\Test.txt c:\ProgramFiles\

Here's the full code of the application:

class Program
{
    static void Main(string[] args)
    {      
            string command = GetCommandLineArugments(args);

            // /c tells cmd that we want it to execute the command that follows and then exit.
            System.Diagnostics.ProcessStartInfo procStartInfo = new System.Diagnostics.ProcessStartInfo("cmd.exe", "/c " + command);

            procStartInfo.RedirectStandardOutput = true;
            procStartInfo.UseShellExecute = false;

            // Do not create the black window.
            procStartInfo.CreateNoWindow = true;
            procStartInfo.WindowStyle = ProcessWindowStyle.Hidden;

            System.Diagnostics.Process process = new System.Diagnostics.Process();
            process.StartInfo = procStartInfo;
            process.Start();

        }

    private static string GetCommandLineArugments(string[] args)
    {
        string retVal = string.Empty;

        foreach (string arg in
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