Edit Question - KnowledgeHub

Title Body

Before you say its a duplicate question, please let me explain (as I've read all similar threads). My application has both of these settings: procStartInfo.CreateNoWindow = true; procStartInfo.WindowStyle = ProcessWindowStyle.Hidden; and is also has WindowsApplication as the output type. The black window STILL comes up when I call a command line command. Is there anything else I can do to hide the window? It doesn't happen for all commands, XCOPY is a situation where it the black window does flash up. This only happens though when the destination I'm XCOPYing too already contains the file and it's prompting me if I want to replace it. Even if I pass in /Y it will still flash briefly. I'm open to using vbscript if that will help, but any other ideas? The client will call my executable and then pass in a command line command ie: C:\MyProgram.exe start XCOPY c:\Test.txt c:\ProgramFiles\ Here's the full code of the application: class Program { static void Main(string[] args) { string command = GetCommandLineArugments(args); // /c tells cmd that we want it to execute the command that follows and then exit. System.Diagnostics.ProcessStartInfo procStartInfo = new System.Diagnostics.ProcessStartInfo("cmd.exe", "/c " + command); procStartInfo.RedirectStandardOutput = true; procStartInfo.UseShellExecute = false; // Do not create the black window. procStartInfo.CreateNoWindow = true; procStartInfo.WindowStyle = ProcessWindowStyle.Hidden; System.Diagnostics.Process process = new System.Diagnostics.Process(); process.StartInfo = procStartInfo; process.Start(); } private static string GetCommandLineArugments(string[] args) { string retVal = string.Empty; foreach (string arg in

Tags (comma-separated) Cancel