I am writing this because I have really hit the wall and cannot go ahead. In my database I have escaped HTML like this: "<p>My name is Freddy and I was".
I want to show it as HTML OR strip the HTML tags in my XSL template. Both solutions will work for me and I will choose the quicker solution.
I have read several posts online but cannot find a solution. I have also tried disable-output-escape with no success. Basically it seems the problem is that somewhere in the XSL execution the engine is changing this <p> into this: &lt;p&gt;.
It is converting the & into &. If it helps, here is my XSL code. I have tried several combinations with and without the output tag on the top.
Any help will be appreciated. Thanks in advance.
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" omit-xml-declaration="yes"/>
<xsl:template match="DocumentElement">
<div>
<xsl:attribute name="id">mySlides</xsl:attribute>
<xsl:apply-templates>
<xsl:with-param name="templatenumber" select="0"/>
</xsl:apply-templates>
</div>
<div>
<xsl:attribute name="id">myController</xsl:attribute>
<xsl:apply-templates>
<xsl:with-param name="templatenumber" select="1"/>
</xsl:apply-templates>
</div>
</xsl:template>
<xsl:template match="DocumentElement/QueryResults">
<xsl:param name="templatenumber">tobereplace</xsl:param>
<xsl:if test="$templatenumber=0">
<div>
<xsl:attribute name="id">myController</xsl:attribute>
<div>
<xsl:attribute name="class">article</xsl:attrib