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I am writing this because I have really hit the wall and cannot go ahead. In my database I have escaped HTML like this: "&lt;p&gt;My name is Freddy and I was" . I want to show it as HTML OR strip the HTML tags in my XSL template. Both solutions will work for me and I will choose the quicker solution. I have read several posts online but cannot find a solution. I have also tried disable-output-escape with no success. Basically it seems the problem is that somewhere in the XSL execution the engine is changing this &lt;p&gt; into this: &amp;lt;p&amp;gt; . It is converting the & into &amp; . If it helps, here is my XSL code. I have tried several combinations with and without the output tag on the top. Any help will be appreciated. Thanks in advance. <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" omit-xml-declaration="yes"/> <xsl:template match="DocumentElement"> <div> <xsl:attribute name="id">mySlides</xsl:attribute> <xsl:apply-templates> <xsl:with-param name="templatenumber" select="0"/> </xsl:apply-templates> </div> <div> <xsl:attribute name="id">myController</xsl:attribute> <xsl:apply-templates> <xsl:with-param name="templatenumber" select="1"/> </xsl:apply-templates> </div> </xsl:template> <xsl:template match="DocumentElement/QueryResults"> <xsl:param name="templatenumber">tobereplace</xsl:param> <xsl:if test="$templatenumber=0"> <div> <xsl:attribute name="id">myController</xsl:attribute> <div> <xsl:attribute name="class">article</xsl:attrib

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